修复掉设备问题

script/ScriptManager.py

@@ -1111,23 +1111,18 @@ class ScriptManager():
                         " or @value='Inbox' or @label='Inbox' or @name='Inbox']"
                     )
 
-                    print("11111111111111")
                     # 查找所有收件箱节点
                     inbox_nodes = session.xpath(xpath_query).find_elements()
-                    print("222222222222222")
                     if len(inbox_nodes) < 2:
                         LogManager.method_error(f"当前页面不再收件箱页面，重启", "检测消息", udid)
                         raise Exception("当前页面不再收件箱页面，重启")
-                    print("33333333333333")
 
                     m = re.search(r'(\d+)', el.label)  # 抓到的第一个数字串
                     count = int(m.group(1)) if m else 0
-                    print("444444444444444444")
 
                     if not count:
                         LogManager.method_info(f"当前收件箱的总数量{count}", "检测消息", udid)
                         break
-                    # print("5555555555555555555555")
 
                     # 新粉丝
                     xp_new_fan_badge = (
@@ -1170,7 +1165,6 @@ class ScriptManager():
                         "[@value and translate(@value,'0123456789','')='']"
                         "/ancestor::XCUIElementTypeCell[1]"
                     )
-                    print("6666666666666666")
 
                     try:
                         # 如果 2 秒内找不到，会抛异常
@@ -1184,7 +1178,6 @@ class ScriptManager():
                         print("当前屏幕没有找到 用户消息 未读徽标数字", udid)
                         user_text = None
                         info_count += 1
-                    print("777777777777777777777")
 
                     if user_text:
 
@@ -1218,11 +1211,11 @@ class ScriptManager():
                                     last_in = item['text']
                                 if last_out is None and item['dir'] == 'out':
                                     last_out = item['text']
-                                if last_in or last_out:  # 任一条拿到就提前停
+                                if last_in and last_out:  # 任一条拿到就提前停
                                     break
 
                             # 2. 只有两条都空才重试
-                            if not last_in and not last_out:
+                            if not last_in or not last_out:
                                 attempt += 1
                                 if attempt == 3:
                                     break  # 三次用完，放弃